Data Structures, Algorithms, & Applications in C++
Chapter 3, Exercise 1

(a)

lim n -> infinity (q(n) / p(n))
= lim n -> infinity (100n2 + 6)/(3n4 + 2n2)
= lim n -> infinity (100/n2 + 6/n4)/(3 + 2/n2)
= 0/3
= 0

(c)

lim n -> infinity (q(n) / p(n))
= lim n -> infinity 10n2/(7n2log n)
= lim n -> infinity (10/log n)/7
= 0/7
= 0