Data Structures, Algorithms, & Applications in C++
Chapter 3, Exercise 1

(b)

lim n -> infinity (q(n) / p(n))
= lim n -> infinity (100n)/(6n1.5 + 12)
= lim n -> infinity (100/n0.5)/(6 + 12/n1.5)
= 0/6
= 0

(d)

lim n -> infinity (q(n) / p(n))
= lim n -> infinity (100n2n + 33n)/(17n22n)
= lim n -> infinity (100/n + 33/(n2n))/17
= 0/17
= 0