/*
   Here is the code for the cups example.  Recall, during lecture we used a series
   of differently colored cups to represent variables and arrays in the program.
   Below is a table where I point out the basic change in the variables as the loop 
   executes.
*/

#include <stdio.h>

int main() {
  int blue[] = {5, 10, 15, 20, 25};
  int black  = 0;
  int red    = 0;
  int clear  = 10;
  int blue_i = 0;

  char headings[8][8] = { "black", "red", "clear", "blue[0]", "blue[1]", "blue[2]", "blue[3]", "blue[4]" };

  printf("\n");
  printf( " %9s %9s %9s %9s %9s %9s %9s %9s\n", headings[0], headings[1], headings[2], headings[3], headings[4], headings[5], headings[6], headings[7] );
  printf("\n");

  for ( black = 0; black < 5; black++, clear = clear + 5 ) {

    if ( ( clear % 10 ) == 0 ) {

      blue[ black ] = blue[ black ] + clear;

    }

    else {

      for ( red = 0; red < 5; red++ ) {

        blue[ red ] = blue[ red ] - ( clear % 10 );

      }

    }

    printf( " %9d %9d %9d", black, red, clear );

    for ( blue_i = 0; blue_i < 5; blue_i++ ) {

      printf( " %9d", blue[ blue_i ] );

    }

    printf("\n");
  }

  printf("\n");
}

/*

The loop runs from 0 to 4, we increment black by one each time thus we will
be in the black loop 5 times.  I do not show the change in clear until the next
iteration of the loop because the change happens at the very end.  Init is the
initial value I have chosen for each variable.


                 Time in the loop            5 - contains final values

Variable    Init     1     2     3     4     5

black    =     0     0     1     2     3     4

red      =     0    ( hard to show in a table like this the red value changing )

clear    =    10    10    15    20    25    30    35 ( note the final value of clear )

blue[0]  =     5    15    10    10     5     5
blue[1]  =    10    10     5     5     0     0
blue[2]  =    15    15    10    30    25    25
blue[3]  =    20    20    15    15    10    10
blue[4]  =    25    25    20    20    15    45


Note the values printed for blue by the code are a transpose ( rows and columns 
flipped )of the table above


Each time we enter the else statement the red variable will start equal to 
zero and then increment: 1 - 2 - 3 - 4 - and finally to 5.  Then the loop 
will exit.  So the final value of red will be 5.  

*/